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Question

The rate of cooling at 600K, if the surrounding temperature is 300K, is H. The rate of cooling at 900K is


A

163H

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B

2H

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C

3H

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D

23H

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Solution

The correct option is A

163H


Step 1: Given data:

The rate of cooling is H at temperature T=600K with the surrounding temperature T0=300K

To find: Rate of cooling is H'=? at temperature T'=900K with surrounding temperature T0=300K

Step 2: Formula used:

According to Stefan's law, the rate of cooling HT4-T04, where T is the given temperature and T0 is the surrounding temperature.

Step 3: Calculation of cooling rate at 900K :

H'T'4-T04HT4-T04

Taking ratio of both above equations,

H'H=T'4-T04T4-T04H'H=9004-30046004-3004H'H=94-3464-34H'H=3434-13424-1H'H=81-116-1H'H=8015H'H=163H'=163H

Thus, the rate of cooling will be 163H.

So, option A is correct.


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