# The ratio of active masses of 22g of CO2, 3g of H2 and 7g of N2 in a gaseous mixture: (A) 22:3:7 (B) 0.5: 3: 7 (C) 1:3:1 (D) 1:3: 0.5

Let V be the volume of gaseous mixture

CO2 = 22/44

= 0.5 moles

H2 = 3/2

= 1.5 moles

N2 = 7/28

= 0.25 moles

Total moles = 0.5 + 1.5 + 0.25

We get,

Total masses = 2.25

Ratio of active masses = 0.5/2.25 : 1.5/2.25 : 0.25/2.25

Ratio of active masses = 1: 3: 0.5

Therefore, the correct option is (D)