The reading of ammeter in the circuit shown will be

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2.4 A

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Zero

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1.7 A

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Solution

The correct option is A 2A
Given $X_{L} = X_{C} = 5 Ω$ this is the condition of resonance. Since $V_{L} = V_{C}$ net voltage across L and C combination will be zero.

Voltage drop across the resistance = 110v. Thus current flowing though Ammeter reading = $\frac{110 v}{55} = 2 A$ .

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