Question

The sum of squares of first ten natural numbers is:

Answer 1

By the formula of sum of firts $n$ natural numbers, we know,

$Sn=\left(\frac{1}{6}\right)n(n+1)(2n+1)$

Here, $n=10$

$S_{10}=\left(\frac{1}{6}\right)10(10+1)(2\times 10+1)$

$S_{10}=\frac{1}{6}(10x11x21)$

$S_{10}=385$

Hence, the sum of squares of first ten natural numbers is $385$.