Question

The sum of three consecutive multiples of $8$ is $888$. Find the multiples

Answer 1

Let, first multiple $=x$, Second multiple $=x+8$, third multiple $=(x+8)+8=x+16$

Now, Sum of multiple$=21$

$$\begin{gathered} \Rightarrow x+(x+8)+(x+16)=888 \\ \Rightarrow x+x+8+x+16=888 \\ \Rightarrow x+x+x+8+16=888 \\ \Rightarrow 3x+24=888 \\ \Rightarrow 3x=888-24 \\ \Rightarrow 3x=864 \\ \Rightarrow x=\frac{864}{3} \\ \Rightarrow x=288 \end{gathered}$$

Therefore,

First integer $=x=288$

Second integer $=x+8=296$

Third integer $=x+16=304$

Thus, the consecutive integers are $288,296,304$.