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Question

The taxi fare after each km when the fare is Rs 15 for the first km and Rs 8 for each additional km. Write the arithmetic progression thus formed.


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Solution

Finding the general fare sequence formed for each km

Taxi fare for the first km is 15 Rs and then it increases by 8 Rs for each km.

The first term a=15 and common difference d=8.

First km fare =15

Second km fare =15+8×(1)=23 .......1 due to additional 1 km travelled aside from the first km.

Third km fare =15+8×(2)=31 .......2 due to additional 2 km travelled aside from the first km.

Fourth km fare =15+8×(3)=39 .......3 due to additional 3 km travelled aside from the first km

Hence, the sequence becomes 15,23,31,39.....


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