Question

The total spin resulting from a $d^7$ configuration is:

Answer 1

Step 1: Finding the number of unpaired electrons in a $d^7$configuration:

• The d orbital has the maximum capacity of$10$ electrons.
• The given $7$electrons are filled in the given standard manner:
• 
• So, the no. of unpaired electrons that we can observe is$3$.

Step 2: Finding the spin of the paired electrons:

• The paired electrons have a spin in opposite directions as shown:
• 
• So, the net movement or spin gets canceled out.
• Hence, the net spin of paired electrons is$0$.

Step 3: Finding the spin of the unpaired electrons:

• The unpaired electrons have a spin in a single direction as shown:
• 
• So, its spin would get added, where each unpaired electron has a spin of$\frac{1}{2}$
• No. of unpaired electrons$=3$
• so, total resulting spin$=\frac{1}{2}+\frac{1}{2}+\frac{1}{2}$.
• Hence, The Total spin$=\frac{3}{2}$.

The total spin resulting from a $d^7$ configuration is $\frac{3}{2}$.