The value of3x3 -9x2 - 27x - 3x is

Find the value of(3x^3 +9x^2 + 27x) ÷ 3x:[ (3x^3 +9x^2 + 27x) ÷ 3x = (3x^3 +9x^2 + 27x)/3x; ...

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Long Division Method to Divide Two Polynomials

The value of3...

Question

The value of $(3 x^{3} + 9 x^{2} + 27 x) \div 3 x$ is

$x^{2} + 9 + 27 x$

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$3 x^{3} + 3 x^{2} + 27 x$

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$3 x^{3} + 9 x^{2} + 9$

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$x^{2} + 3 x + 9$

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Solution

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Similar questions

(3 x^{3} + 9 x^{2} + 27 x) \div 3 x

x^{2} + 9 + 27 x

3 x^{3} + 3 x^{2} + 27 x

3 x^{3} + 9 x^{2} + 9

x^{2} + 3 x + 9

(3 x^{3} + 9 x^{2} + 27 x) \div 3 x

x^{2} + 9 + 27 x

3 x^{3} + 3 x^{2} + 27 x

3 x^{3} + 9 x^{2} + 9

x^{2} + 3 x + 9

x^{4} - 3 x^{3} + 9 x^{2} - 27 x + 81

(x - 3)

lim x \to 1 \frac{x^{4} + 3 x^{3} - {13 x}^{2} - 27 x + 36}{x^{2} + 3 x - 4}

x^{4} + \frac{8}{9} x^{2} + 1 = 3 x^{3} + 3 x

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