Question

Where is the value of ‘g’ minimum on earth?

Answer 1

1. The equation of acceleration due to gravity is $g=\frac{GM}{R^2}$
2. This implies that g is inversely proportional to the radius of the earth.
3. R is the largest at the equator.
4. Also, g varies with the latitude of the earth due to the centrifugal force of rotation of the earth
5. The variation of g with latitude $\lambda$ is given by the equation $g^{\text{'}}=g-w^2{R}^2{\cos }^2\lambda$
6. Hence g is minimum at the equator where $\lambda =0$ and $g_{equator}=g-w^2{R}^2$

Therefore g is minimum at the equator