Question

The work function of a Photoelectric material is $3.3eV$. Its threshold frequency will be​

Answer 1

Step 1: Given data

$W=$work function$=3.3ev=3.3\times 1.6\times {10}^{-19}Joules$

Step 2: Formula used

$W=h\nu$, where $W=$work function$=3.3ev=3.3\times 1.6\times {10}^{-19}Joules$, $h=$Planck's constant$=6.6\times {10}^{-34}$, $\nu =$threshold frequency

Step 3: Calculation for Threshold Frequency

So, $3.3\times 1.6\times {10}^{-19}=6.6\times {10}^{-34}\times \nu$

$$\begin{gathered} \Rightarrow \nu =\frac{3.3\times 1.6\times {10}^{-19}}{6.6\times {10}^{-34}} \\ \Rightarrow v=0.8\times {10}^{15} \\ \Rightarrow v=8\times {10}^{14}Hz \end{gathered}$$

Hence, the threshold frequency will be​ $8\times {10}^{14}Hz$.