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Question

The work function of Sodium is2.75eV. What will be the Kinetic energy of emitted electron when the Photon of energy 3.54eVis incident on the surface of Sodium?


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Solution

Kinetic Energy

  • The photon energy incident on the metal surface is equal to the sum of the metal's work function and the electron's maximum kinetic energy.
  • hf=K.E+ϕ

Where

  • hf-Photon energy
  • K.E-Kinetic energy
  • ϕ-Work function

Then, Kinetic Energy is given by

  • K.E=hf-ϕ

Here given that

  • ϕ=2.75eV
  • hf=3.54eV

Now

  • K.E=hf-ϕ
  • K.E=3.54-2.75
  • K.E=0.79eV

Therefore, the Kinetic energy of the emitted electron is 0.79eV


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