Three coins are tossed at once. What is the probability of two heads and one tail?

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Solution

Find the probability of two heads and one tail:
Three coins are tossed at once.
The possible outcomes will be $(H H H, T T T, H T T, T H T, T T H, T H H, H T H, H H T)$ .
We have to find the probability of two heads and one tail:
So, favorable outcomes $= T H H, H T H, H H T$
$Number of favourable outcomes = 3$
Hence required probability is:
$Probability of event to happen P (E) = \frac{Number of favourable outcomes}{Total Number of outcomes}$
$Probability (2 H & 1 T) = \frac{3}{8}$
Hence, when $3$ coins are tossed, the probability of two heads and one tail is $\frac{3}{8}$ .

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