Three letters are drawn from alphabets of $26$ letters without replacement. The probability that letters appear orderly is

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Solution

Total number of ways $3$ letters can be selected $3! = 6$
One out of $6$ ways will be in an ordered form.
Therefore, $P = \frac{1}{6}$
Hence, the probability that letter appears orderly is $\frac{1}{6}$ .

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Three letters are drawn from alphabets of 26 letters without replacement. The probability that letters appear orderly is

Total number of ways 3letters can be selected 3!=6One out of 6 ways will be in an ordered form.Therefore, P=16Hence, the probability that letter appears orderly is 16.

Three letters are drawn from alphabets of $26$ letters without replacement. The probability that letters appear orderly is

Total number of ways $3$ letters can be selected $3! = 6$
One out of $6$ ways will be in an ordered form.
Therefore, $P = \frac{1}{6}$
Hence, the probability that letter appears orderly is $\frac{1}{6}$ .