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Standard VI

Mathematics

Constructing a Line Segment of a Given Length

To divide a l...

Question

To divide a line segment $A B$ in the ratio $5 : 7$ , first a ray $A X$ is drawn so that $B A X$ is an acute angle and then at equal distances points are marked on the ray $A X$ such that the minimum number of these points is

$8$

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$10$

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$11$

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$12$

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Solution

The correct option is D
$12$

Let's find the minimum number of points.
According to the given details, we know that
A line segment $A B$ in the ratio $5 : 7$
So, $A : B = 5 : 7$
Draw a ray $A X$ making an acute angle $∠ B A X$ ,
Mark $A + B$ points at equal distance.
So, we have $A = 5$ and $B = 7$
Hence, minimum number of these points $A + B = 5 + 7 = 12$

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To divide a line segment ABin the ratio 5:7, first a ray AX is drawn so that BAXis an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is

To divide a line segment $A B$ in the ratio $5 : 7$ , first a ray $A X$ is drawn so that $B A X$ is an acute angle and then at equal distances points are marked on the ray $A X$ such that the minimum number of these points is