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Standard XII

Physics

Free Body Diagrams

Two blocks m1...

Question

Two blocks $m_{1} = 300 g$ and $m_{2} = 500 g$ are pushed by force $F$ . If the coefficient of friction is $0.40$ . What must be the value of $F$ if the blocks are to have an acceleration of $200 \frac{cm}{s^{2}}$ .

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Solution

Step 1: Given data
$m_{1} = 300 g$
$m_{2} = 500 g$
$μ = 0.40$
$a = 200 \frac{cm}{s^{2}}$
Step 2: To find
We have to find the value of $F$ .
Step 3: Calculate the value of force
We know that,
$F_{g 1} = F_{N 1}$ and,
$F_{g 2} = F_{N 2}$
$\sum F_{x} = F - F_{1} - F_{2} = m_{T} a = m_{T} a - F_{1} - F_{2} = m_{T} a + μ F_{N T} = m_{T} a + μ m_{T} g$
By substituting the given values, we get
$= 0.8 (2) + 0.4 (0.8) 9.8 = 4.7 N$
Therefore, the value of $F$ is $4.7 N$ .

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Two blocks m1=300g and m2=500g are pushed by force F. If the coefficient of friction is 0.40. What must be the value of F if the blocks are to have an acceleration of 200cms2.

Two blocks $m_{1} = 300 g$ and $m_{2} = 500 g$ are pushed by force $F$ . If the coefficient of friction is $0.40$ . What must be the value of $F$ if the blocks are to have an acceleration of $200 \frac{cm}{s^{2}}$ .