Two chords $A B$ and $C D$ of a circle are each at distances $4 c m$ from the centre. Then $A B = C D$ .
Write True or False and justify your answer in each of the following:

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A True
Given that $A B$ and $A C$ are chords that are at a distance of $4 c m$ from the centre of a circle.
Since, chords that are equidistant from the centre of a circle are equal in length,
We get $A B = C D .$

Suggest Corrections

Similar questions

A B

C D

4

A B

C D

If each of two chords, $A B$ and $C D$ , of a circle are at a distance of 4 cm from the centre, then $A B = C D$ .

A B

C D

4 c m

A B - C D

Two chords AB and CD of a circle are each at a distance of 5 cm from centre. Then AB=CD

Join BYJU'S Learning Program