Using a-2 - b-2 - -a - b-a - b- find -i- 153-2 - 147-2 -ii- 12-1-2 - 7-9-2 - Maths Q-A

Using the identitya^2 b^2 = (a + b)(a b)Puttinga = 153 , b = 147we get, 153^2 – 147^2= (153 + 147)(153 – 147) 0ex0ex153^2 – 147^2= 300 × 60ex0ex153^2 – 147 ...

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Byju's Answer

Standard VIII

Mathematics

(x+y)^2 + (x-y)^2 and (x+y)^2 - (x-y)^2

Using a^2 - b...

Question

Using $a^{2} - b^{2} = (a + b) (a - b)$ , find
$153^{2} - 147^{2}$

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Solution

Using the identity
$a^{2} - b^{2} = (a + b) (a - b)$
Putting
$a = 153, b = 147$
we get,
$153^{2} - 147^{2} = (153 + 147) (153 - 147) 153^{2} - 147^{2} = 300 \times 6 153^{2} - 147^{2} = 1800$
Hence, $153^{2} - 147^{2} = 1800$

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Similar questions

Q. Using

a^{2} - b^{2} = (a + b) (a - b)

, find

153^{2} - 147^{2}

Q. Using

a^{2} - b^{2} = (a + b) (a - b),

find
1)

51^{2} - 49^{2}

{(1.02)}^{2} - {(0.98)}^{2}

153^{2} - 147^{2}

{12.1}^{2} - {7.9}^{2}

Using a²−b² = (a + b) (a − b),find

(i) 51² −49² (ii) (1.02)² − (0.98)² (iii) 153² − 147²

(iv) 12.1² −7.9²

Using a²− b² = (a + b) (a − b), find

(i) 51² − 49² (ii) (1.02)² − (0.98)² (iii) 153² − 147²

(iv) 12.1² − 7.9²

Q. Question 7(iii)
Using

a^{2} - b^{2} = (a + b) (a - b),

find

153^{3} - 147^{2}

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Using a2-b2=(a+b)(a-b), find 1532-1472

Using the identitya2-b2=(a+b)(a-b)Puttinga=153,b=147we get, 1532–1472=(153+147)(153–147)1532–1472=300×61532–1472=1800Hence, 1532-1472=1800

Using $a^{2} - b^{2} = (a + b) (a - b)$ , find
$153^{2} - 147^{2}$

Using the identity
$a^{2} - b^{2} = (a + b) (a - b)$
Putting
$a = 153, b = 147$
we get,
$153^{2} - 147^{2} = (153 + 147) (153 - 147) 153^{2} - 147^{2} = 300 \times 6 153^{2} - 147^{2} = 1800$
Hence, $153^{2} - 147^{2} = 1800$