Question

The velocity of a certain monochromatic light is $2.25\times {10}^8\frac{\text{m}}{\text{s}}$ to the given transparent medium. Find polarization angle for this medium.

Answer 1

Step 1:Given parameters

The velocity of monochromatic light, $v=2.25\times {10}^8\frac{\text{m}}{\text{s}}$.

Step 2: Calculate polarization angle

$\tan i_p=\frac{c}{v}$

Where, $c$ is the velocity of the light and $i_p$ is the polarization angle.

$$\begin{gathered} \tan i_p=\frac{3\times {10}^8}{2.25\times {10}^8} \\ \tan i_p=1.33 \\ {i}_p=53.06° \end{gathered}$$

Hence, the polarization angle is $53.06°$