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Question

Vinegar is a solution of


A

50%-60%acetic acid in alcohol

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B

5%-8%acetic acid in alcohol

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C

5%-8%acetic acid in water

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D

50%-60%acetic acid in water

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Solution

The correct option is C

5%-8%acetic acid in water


Explanation for the correct option:

(c) 5%-8%acetic acid in water

Vinegar

  • Vinegar is a dilute aqueous solution of Acetic acid.
  • The molecular formula of Acetic acid isCH3COOH. IUPAC's name is Ethanoic acid.
  • Acetic is a colorless liquid.

Preparation

  • Vinegar is prepared by diluting 5%-8%acetic acid in water.
  • Only less concentration of acetic acid is used as vinegar is used for cooking.

Therefore, (c) 5%-8%acetic acid in water is correct.

Explanation for the incorrect options:

(a) 50%-60%acetic acid in alcohol

  • When acetic acid reacts with alcohol it forms Ester. The process is esterification.
  • CH3COOH(l)+CH3CH2OH(l)H2SO4CH3COOCH2CH3(l)+H2O(l)(Aceticacid)(Ethanol)(Ethylacetate)(Water)
  • So, Acetic acid in alcohol does not form Vinegar.

(b) 5%-8%acetic acid in alcohol

  • When acetic acid reacts with alcohol it forms Ester. The process is esterification.
  • So, Acetic acid in alcohol does not form Vinegar.

(d) 50%-60%acetic acid in water

  • Vinegar is a dilute aqueous solution of Acetic acid.
  • Only less concentration of acetic acid
  • Higher concentrations of acetic acid should not be used as the vinegar is used for cooking.

Hence, Option (c) 5%-8%acetic acid in water is correct.


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