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Question

What can the maximum number of digits be in the repeating block of digits in the decimal expansion of 117? Perform the division to check your answer.


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Solution

Find maximum number of digits be in the repeating block of digits in the decimal expansion of 117.

Divide 1 by 17

117=0.0588235294117647¯

There are 16 digits in the repeating block of the decimal expansion of 117.

The remainder never becomes zero and remainders repeat after a certain stage.

Thus, there are 16 digits in the repeating block of the decimal expansion of 117.


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