Question

What is the angle of rotation symmetry for a shape that has rotational symmetry of order $5$?

Answer 1

The angle of rotation of symmetry:

The angle of rotation of symmetry is computed as,

$\mathrm{Angle}\mathrm{of}\mathrm{rotation}=\frac{360°}{\mathrm{Order}\mathrm{of}\mathrm{symmetry}}$

Given that, the order of symmetry is $5$.

$$\begin{gathered} \therefore \mathrm{Angle}\mathrm{of}\mathrm{rotation}=\frac{360°}{5} \\ \Rightarrow =72° \end{gathered}$$

Hence, the angle of rotation of symmetry is $72°$.