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Question

What is the bond order of NO and NO+?


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Solution

Bond Order

  • Bond order is defined as one-half the difference between the number of electrons present in the bonding and the antibonding orbitals.
  • The mathematical formula is as follows,
  • Bond order (B.O.)=12 (number of electrons in the bonding orbitals) - (number of electrons in the antibonding orbitals)

Bond order of NO

  • The electronic configuration is as follows
  • σ1s2,σ*1s2,σ2s2,σ*2s2,σ2px2,π2py2,π2pz2,π*2px1
  • Bond order NO=12(10-5)
  • Bond order NO=2.5

Bond order of NO+

  • The electronic configuration is as follows
  • σ1s2,σ*1s2,σ2s2,σ*2s2,σ2px2,π2py2,π2pz2
  • Bond order of NO+=12 (number of electrons in the bonding orbitals) - (number of electrons in the antibonding orbitals)
  • Bond order NO+=12(10-4)
  • Bond order NO+=3

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