What is the derivative of cosecx?
Determine the derivative of cosecx.
Let,y=cosecx⇒y=1sinx⇒y=(sinx)-1
Use the formula of the chain rule
y=f(g(x))⇒dydx=f'(g(x))×g'(x)
Now calculate the derivative:
dydx=-(sinx)-2×ddx(sinx)⇒dydx=-cosxsinx×1sinx⇒dydx=-cotx.cosecx
Hence, the derivative of cosecx is"-cotxcosecx".
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