Question

What is the full ground state electron configuration of $\mathrm{O}$?

Answer 1

Electronic configuration

• It is defined as the distribution of electrons of an atom in different atomic orbitals.
• The general notation of electronic configuration is ${\mathrm{s}}^{\mathrm{a}}{\mathrm{p}}^{\mathrm{b}}{\mathrm{d}}^{\mathrm{c}}$ where $\mathrm{s},\mathrm{p},$ and $\mathrm{d}$ represent the subshell and $\mathrm{a},\mathrm{b}$ and $\mathrm{c}$ represents the number of electrons present in the subshell as superscript.

Oxygen $\mathbf{\left(}\mathbf{O}\mathbf{\right)}$

Atomic number of oxygen $=8$

• As the atomic number is equal to the number of electrons present in a neutral element. So, the number of electrons are $8$.
• The ground state electronic configuration for oxygen is $1s^{\mathit{2}}\mathit{2}{s}^{\mathit{2}}2p^{\mathit{4}}$.