Question

Write the first four terms of the A.P. when the first term $a$ and the common difference $d$ are given as follows: $\left(v\right)a=-1.25,d=-0.25$

Answer 1

Solution.

The $nth$term of an A.P. is given by the expression,

$a_n=a+(n-1)d$

Where $a$ is the first term and $d$ is the common difference.

We have to find the first four terms of the A.P. which has$a=-1.25,d=-0.25$.

$$\begin{gathered} a_1=a=-1.25 \\ {a}_2=a+d=-1.25+(-0.25)=-1.5 \\ {a}_3=a+2d=-1.25+2(-0.25)=-1.75 \\ {a}_4=a+3d=-1.25+3(-0.25)=-2 \end{gathered}$$

Hence, the first four terms of the given A.P. are $-1.25,-1.5,-1.75,-2$.