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Question

What is the molar solubility (s) of Ba3(PO4)2 in terms of Ksp?


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Solution

Step 1: Solubility product:

  • Ksp can be called a solubility product or the solubility constant.
  • Consider, “the equilibrium between the undissolved solid and the ions in a saturated solution”. This can be represented by the equation:

Ba3PO42(s)Saturatedsolutioninwater3Ba2+(aq)+2PO43-(aq)

  • The equilibrium constant is given by equation:

Ksp=Ba2+3PO43-2Ba3PO42

  • For a pure solid substance, the concentration remains constant and it can be written as:

Ksp=KBa3PO42=Ba2+3PO43-2

Step 2: Calculation of Solubility product:

  • For solid barium phosphate in equilibrium with its saturated solution, the product of the concentrations of barium and phosphate ions is equal to its solubility product constant.
  • The concentrations of the two ions will be equal to the molar solubility of the barium phosphate.
  • If molar solubility is S, then the solubility product will be:

Ksp=Ba2+3PO43-2Ksp=3S32S2


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