Question

What is the value of $\begin{array}{l}{248}^2-{249}^2\end{array}$?

Answer 1

Find the value of$\begin{array}{l}{248}^2-{249}^2\end{array}$.

Apply the algebraic identity $a^2-b^2=\left(a+b\right)\left(a-b\right)$ in the given equation.

$\begin{array}{rcl}{248}^2-{249}^2& =& \left(248+249\right)\left(248-249\right)\\ & =& \left(497\right)\left(-1\right)\\ & =& -497\end{array}$

Hence, the value of $\begin{array}{rcl}& & {248}^2-{249}^2\end{array}$ is $\begin{array}{rcl}& & -497\end{array}$