What will be the input of A and B for Boolean expression (A+B¯)(A.B¯)=1?
0,0
0,1
1,0
1,1
The explanation for the correct result:
Option A:
A=0B=0
Now,
(A+B¯)(A.B¯)=(0+0¯)(0.0¯)=(0¯)(0¯)=(1)(1)=1
The explanation for the incorrect result:
Option B:
A=0B=1
So,
(A+B¯)(A.B¯)=(0+1¯)(0.1¯)=(0)(1)=0
Option C:
A=1B=0
(A+B¯)(A.B¯)=(1+0¯)(1.0¯)=(0)(1)=0
Option D:
A=1B=1
(A+B¯)(A.B¯)=(1+1¯)(1.1¯)=(0)(0)=0
Hence, option A is the correct answer.