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Question

What will be the input of A and B for Boolean expression (A+B¯)(A.B¯)=1?


A

0,0

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B

0,1

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C

1,0

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D

1,1

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Solution

The correct option is A

0,0


The explanation for the correct result:

Option A:

A=0B=0

Now,

(A+B¯)(A.B¯)=(0+0¯)(0.0¯)=(0¯)(0¯)=(1)(1)=1

The explanation for the incorrect result:

Option B:

A=0B=1

So,

(A+B¯)(A.B¯)=(0+1¯)(0.1¯)=(0)(1)=0

Option C:

A=1B=0

So,

(A+B¯)(A.B¯)=(1+0¯)(1.0¯)=(0)(1)=0

Option D:

A=1B=1

So,

(A+B¯)(A.B¯)=(1+1¯)(1.1¯)=(0)(0)=0

Hence, option A is the correct answer.


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