Question

When ${\mathrm{KMnO}}_4$ Reacts With${\mathrm{H}}_2{\mathrm{O}}_2$In Slightly Alkaline. Which of the following chemical element is formed?

• A. ${\mathrm{MnO}}_2$
• B. ${\mathrm{Mn}}^{+7}$
• C. ${\mathrm{Mn}}^{+2}$
• D. ${\mathrm{Mn}}_2{\mathrm{O}}_3$

Answer 1

The correct option is C

${\mathrm{Mn}}^{+2}$

Explanation for correct option:

(C) ${\mathrm{Mn}}^{+2}$

Step 1: Reaction between ${\mathrm{KMnO}}_4$ With${\mathrm{H}}_2{\mathrm{O}}_2$In Slightly Alkaline medium:

• ${\mathrm{MnSO}}_4$ is formed when ${\mathrm{KMnO}}_4$ reacts with ${\mathrm{H}}_2{\mathrm{O}}_2$ in a slightly alkaline media. The balanced reaction is$5{\mathrm{H}}_2{\mathrm{O}}_2+2{\mathrm{KMnO}}_4+3{\mathrm{H}}_2{\mathrm{SO}}_4\to 5{\mathrm{O}}_2+2{\mathrm{MnSO}}_4+{\mathrm{K}}_2{\mathrm{SO}}_4+8{\mathrm{H}}_2\mathrm{O}$

Step 2: Analyzing products:

• $[\stackrel{+7}{{\mathrm{KMnO}}_4}\to \stackrel{+2}{{\mathrm{MnSO}}_4}]$
• In ${\mathrm{MnSO}}_4$​, $\mathrm{Mn}$ is in $+2$ oxidation state, hence ${\mathrm{Mn}}^{+2}$ is formed.

Explanation for incorrect options :

(A) ${\mathrm{MnO}}_2$

• On reaction between ${\mathrm{KMnO}}_4$ With${\mathrm{H}}_2{\mathrm{O}}_2$in Slightly Alkaline medium ${\mathrm{MnSO}}_4$ is formed.
• This option states ${\mathrm{MnO}}_2$ to be the product.

(B) ${\mathrm{Mn}}^{+7}$

• On reaction between ${\mathrm{KMnO}}_4$ With${\mathrm{H}}_2{\mathrm{O}}_2$in Slightly Alkaline medium ${\mathrm{MnSO}}_4$ is formed.
• This option states ${\mathrm{MnO}}_2$ to be the product.

(D) ${\mathrm{Mn}}_2{\mathrm{O}}_3$

• On reaction between ${\mathrm{KMnO}}_4$ With${\mathrm{H}}_2{\mathrm{O}}_2$in Slightly Alkaline medium ${\mathrm{MnSO}}_4$ is formed.
• This option states ${\mathrm{Mn}}_2{\mathrm{O}}_3$ to be the product.

Hence, the correct option (C) i.e. ${\mathrm{Mn}}^{+2}$ .