Question

When sodium sulphate solution reacts with barium chloride solution, the solution after the reaction contains

• A. Barium sulphide
• B. Sodium chloride
• C. Both A and B
• D. None of A and B

Answer 1

The correct option is B

Sodium chloride

Explanation for Correct option:

(B) Sodium chloride.

• When sodium sulfate reacts with barium chloride exchange of ions occurs and forms barium sulfate and sodium chloride.
• It is an example of a double displacement reaction.
• The sodium chloride dissolves in the solution and barium sulfate forms an insoluble product.

${\mathrm{Na}}_2{\mathrm{SO}}_4\left(\mathrm{aq}\right)+{\mathrm{BaCl}}_2\left(\mathrm{aq}\right)\to {\mathrm{BaSO}}_4\left(\mathrm{s}\right)\downarrow +2\mathrm{NaCl}\left(\mathrm{aq}\right)$

Explanation for incorrect option:

(A) Barium sulfide.

• When sodium sulfate reacts with barium chloride barium sulfate and sodium chloride will be formed, the anion present is sulfate ion $\left({{\mathrm{SO}}_4}^{2-}\right)$ not sulfide anion $\left({\mathrm{S}}^{2-}\right)$.

(C) Both A and B

• When sodium sulfate and barium chloride reacts it forms barium sulfate and sodium chloride, not barium sulfide as in option (A).

(D) None of A and B

• When sodium sulfate and barium chloride reacts it forms barium sulfate and sodium chloride, and option B sodium chloride will be formed.