Question

Which among ${43}^2,{67}^2,{52}^2,{59}^2$ would end with digit $1$?

• A. ${43}^2$
• B. ${67}^2$
• C. ${52}^2$
• D. ${59}^2$

Answer 1

The correct option is D

${59}^2$

Explanation for the correct option:

Determine among ${43}^2,{67}^2,{52}^2,{59}^2$ would end with a digit $1$

From the properties of a square, we know that if a number ends with $1or9$, then its square will always end with $1$

$$\begin{gathered} {43}^2=1849 \\ {67}^2=4489 \\ {52}^2=2704 \\ {59}^2=3481 \end{gathered}$$

Hence, the correct answer is “option D”.