Question

Which Of The Following Will Not Occur?

• A. $\mathrm{CuO}\left(\mathrm{s}\right)+{\mathrm{H}}_2\left(\mathrm{g}\right)⟶\mathrm{Cu}\left(\mathrm{s}\right)+{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$
• B. $\mathrm{Fe}\left(\mathrm{s}\right)+{\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{l}\right)⟶{\mathrm{H}}_2\left(\mathrm{g}\right)+{\mathrm{FeSO}}_4\left(\mathrm{l}\right)$
• C. $\mathrm{KBr}\left(\mathrm{s}\right)+{\mathrm{I}}_2\left(\mathrm{l}\right)⟶2\mathrm{Kl}\left(\mathrm{s}\right)+{\mathrm{Br}}_2\left(\mathrm{l}\right)$
• D. $\mathrm{Cu}\left(\mathrm{s}\right)+2{\mathrm{AgNO}}_3\left(\mathrm{l}\right)⟶\mathrm{Cu}{\left({\mathrm{NO}}_3\right)}_2\left(\mathrm{l}\right)+2\mathrm{Ag}\left(\mathrm{s}\right)$

Answer 1

The correct option is C

$\mathrm{KBr}\left(\mathrm{s}\right)+{\mathrm{I}}_2\left(\mathrm{l}\right)⟶2\mathrm{Kl}\left(\mathrm{s}\right)+{\mathrm{Br}}_2\left(\mathrm{l}\right)$

Explanation for the correct option:

(c ) $\mathrm{KBr}\left(\mathrm{s}\right)+{\mathrm{I}}_2\left(\mathrm{l}\right)⟶2\mathrm{Kl}\left(\mathrm{s}\right)+{\mathrm{Br}}_2\left(\mathrm{l}\right)$

• Iodine is less reactive than potassium in the reactivity series.
• As a result, Iodine cannot remove potassium from $\mathrm{KBr}$.
• As a result, $\mathrm{KBr}\left(\mathrm{s}\right)+{\mathrm{I}}_2\left(\mathrm{l}\right)⟶2\mathrm{Kl}\left(\mathrm{s}\right)+{\mathrm{Br}}_2\left(\mathrm{l}\right)$ will not occur.
• Hence this option is correct

Explanation for the incorrect options:

(a) $\mathrm{CuO}\left(\mathrm{s}\right)+{\mathrm{H}}_2\left(\mathrm{g}\right)⟶\mathrm{Cu}\left(\mathrm{s}\right)+{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$

• Hydrogen is oxidized when it obtains oxygen and creates water in this reaction.
• Copper oxide, on the other hand, loses oxygen and so becomes reduced.
• As a result, $\mathrm{CuO}\left(\mathrm{s}\right)+{\mathrm{H}}_2\left(\mathrm{g}\right)⟶\mathrm{Cu}\left(\mathrm{s}\right)+{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$ will occur.
• Hence this option is not correct

(b)$\mathrm{Fe}\left(\mathrm{s}\right)+{\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{l}\right)⟶{\mathrm{H}}_2\left(\mathrm{g}\right)+{\mathrm{FeSO}}_4\left(\mathrm{l}\right)$

• iron is more reactive than hydrogen
• As a result, $\mathrm{Fe}\left(\mathrm{s}\right)+{\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{l}\right)⟶{\mathrm{H}}_2\left(\mathrm{g}\right)+{\mathrm{FeSO}}_4\left(\mathrm{l}\right)$ will occur.
• Hence this option is not correct

(d) $\mathrm{Cu}\left(\mathrm{s}\right)+2{\mathrm{AgNO}}_3\left(\mathrm{l}\right)⟶\mathrm{Cu}{\left({\mathrm{NO}}_3\right)}_2\left(\mathrm{l}\right)+2\mathrm{Ag}\left(\mathrm{s}\right)$

• Copper is more reactive than silver in the reactivity series.
• As a result, it can remove silver from ${\mathrm{AgNO}}_3$
• As a result, $\mathrm{Cu}\left(\mathrm{s}\right)+2{\mathrm{AgNO}}_3\left(\mathrm{l}\right)⟶\mathrm{Cu}{\left({\mathrm{NO}}_3\right)}_2\left(\mathrm{l}\right)+2\mathrm{Ag}\left(\mathrm{s}\right)$ will occur.
• Hence this option is not correct

Hence the correct option is (c ) $\mathrm{KBr}\left(\mathrm{s}\right)+{\mathrm{I}}_2\left(\mathrm{l}\right)⟶2\mathrm{Kl}\left(\mathrm{s}\right)+{\mathrm{Br}}_2\left(\mathrm{l}\right)$