Question

Which set of quantum numbers is correct with n = 3?

• A. $\mathrm{l}=3,{\mathrm{m}}_1=+3$
• B. $\mathrm{l}=2,{\mathrm{m}}_1=+2$
• C. $\mathrm{l}=2,{\mathrm{m}}_1=+3$
• D. $\mathrm{l}=4,{\mathrm{m}}_1=-1$

Answer 1

The correct option is B

$\mathrm{l}=2,{\mathrm{m}}_1=+2$

Explanation for correct answer:-

Option (B) $\mathrm{l}=2,{\mathrm{m}}_1=+2$

• We know that for n=3, we have the values of l as $(0,1,2)$
• Now every possible value for $\mathrm{l}\mathrm{and}{\mathrm{m}}_1$are:

$\mathbf{l}$	${\mathbf{m}}_{\mathbf{1}}$
$0$	$0$
$1$	$-1,0,+1$
$2$	$-1,-2,0,+1,+2$

• Therefore, we can clearly see that $\mathrm{l}=2,{\mathrm{m}}_1=+2$ lies in the case for the 3rd option.
• Hence it is the correct option.

Therefore, option (B) $\mathrm{l}=2,{\mathrm{m}}_1=+2$is the correct answer.