Question

Work out the following division: $(10x-25)÷5$

Answer 1

Divide $(10x-25)÷5$.

Cancel out the common factors.

$\begin{array}{rcl}(10x-25)÷5& =& \frac{(10x-25)}{5}\\ & =& \frac{5\left(2x-5\right)}{5}\\ & =& \left(2x-5\right)\end{array}$

Therefore, the required quotient is $\left(2x-5\right)$.