Write 2log3+3log5+5log2 as a single logarithm.
Use, nlogm=logmn
Then,
2log3+3log5+5log2=log32+log52+log25
Use, loga+logb+logc=log(abc)
2log3+3log5+5log2=log32+log52+log25=log32×52×25=log9×25×32=log9×25×32=log3600
Thus, 2log3+3log5+5log2 can be written as a single logarithm as log36000.
Now write these as a single power:
(i) (52)4
(ii) (102)5
(iii) (24)3 × 25