Question

$x–0=$____________ when$3x=12$.

Answer 1

Step 1: Solve the given equation

Solve the equation$3x=12$:

$\begin{array}{rcl}& \Rightarrow & 3x=12\\ & \Rightarrow & x=\frac{12}{3}\\ & \Rightarrow & x=4\end{array}$

Step 2: Fill the blank

Put $x=4$ in $x–0$

We get,

$$\begin{gathered} x–0=4-0 \\ \Rightarrow x–0=4 \end{gathered}$$

$\therefore x–0\underline{=4}$ when$3x=12$.

Hence $x–0\underline{=4}$ when$3x=12$.