Question

Fill in the blanks:

${\mathrm{XeF}}_4$ on partial hydrolysis produces$\mathrm{\_\_\_\_}$.

Answer 1

${\mathrm{XeF}}_4$ on partial hydrolysis produces xenon oxydifluoride $\left({\mathrm{XeOF}}_2\right)$.

Reaction of xenon fluorides with water:

• When ${\mathrm{XeF}}_4$ is partially hydrolyzed, it yields Xenon Oxyfluorides $\mathrm{XeO}{\mathrm{F}}_2$.
• This reaction can be represented as:
  $$\begin{gathered} \mathrm{Xe}{\mathrm{F}}_4\left(\mathrm{g}\right)+{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)\to \mathrm{XeO}{\mathrm{F}}_2\left(\mathrm{g}\right)+2\mathrm{HF}\left(\mathrm{g}\right) \\ \mathrm{Xenon}\mathrm{fluoride}+\mathrm{water}\to \mathrm{xenon}\mathrm{oxydifluoride}+\mathrm{hydrogen}\mathrm{fluoride} \end{gathered}$$