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Question

A car moving with a speed of 40kmh-1 can be stopped by applying brakes after at least 2m. If the same car is moving with a speed of 80kmh-1., what is the minimum stopping distance


A

8m

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B

2m

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C

4m

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D

6m

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Solution

The correct option is A

8m


Step 1. Given data

For case 1-

Initial velocity of the car, u1=40kmh-1

u1=11.11ms-1

Final velocity of the car, v1=0

Distance=2m

For case 2-

Initial velocity of the car, u2=80kmh-1

u2=22.22ms-1

Final velocity of the car, v2=0

Step 2. Finding the acceleration in the first case

By using the equation of motion

v12=u12+2as

0=11.112+2×a×2

a=-11.11×11.112×2

a=-30.85ms-2

STEP 3. Finding the minimum stopping distance

Again, using the equation of motion

v22=u22-2as

0=22.222+2×-30.85×s

s=22.22×22.222×30.85

s=8m

Therefore, the minimum stopping distance is 8m

Hence, the correct option is A


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