A lift is moving down with acceleration a. A man in the lift drops a ball inside the lift. The acceleration of the ball as observed by the man in the lift and a man standing stationary on the ground are respectively

1) g, g

2) g – a, g – a

3) g – a, g

4) a, g

Answer: 3) g – a, g

Solution:

For a man standing in the lift, the acceleration of the ball will be g – a

For a man standing on the ground, the acceleration of the ball will be g – 0 = g

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