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Question

After inserting n A.M's between 2and 38, the sum of the resulting progression is 200.

The value of n is


A

10

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B

8

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C

9

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D

None of these

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Solution

The correct option is B

8


The explanation for the correct option:

Step1. Given data:

First-term, a=2

Last term, l=38

The number of A.M's inserted between a and l = n terms.

Then the number of terms inserted between a and l = n+2 terms

Sum of the progression, Sn=200

The formula for the sum of nterms of A.P, is Sn=n2(a+l)

Step2, Find the value of n:

Now, putting the value of a,land n

Sn+2=n+22(2+38)

200=n+22(40)

400=(n+2)(40)

10=n+2

n=8

Hence, option (B) is the correct answer.


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