(cot215°-1)(cot215°+1)=
12
32
334
3
Explanationforthecorrectoption:option(B):Given,
We know that,
⇒cotθ=1tanθ=1tan15°2-11tan15°2+1=1-tan215°tan215°1+tan215°tan215°=1-tan215°1+tan215°⇒cos2θ=1-tan2θ1+tan2θ⇒θ=15°⇒cos2×15°=cos30°⇒32
Hence, option B is correct.
cot215∘−1cot215∘+1 =
Let B = {1 orange, 1 pineapple, 1 banana, 1 apple} Let U = {1 orange, 1 apricot, 1 pineapple, 1 banana, 1 mango, 1 apple, 1 kiwifruit}
B’ =
(11111111)2 equals: