Question

Force of $50N$ acting on a body at an angle $\theta$ with horizontal. If $150J$ work is done by displacing it $3m$, then $\theta$is

• A. $60°$
• B. $30°$
• C. $0°$
• D. $45°$

Answer 1

The correct option is C

$0°$

Step 1 : Given data

Force $=50N$

Workdone $=150J$

Displacement $=3m$

Angle (horizontal ) $=\theta$

Step 2: To find the angle $\theta$

Horizontal component of force $=F\cos \theta$

Therefore , Work done $W=\left(F\cos \theta \right)\times 3$

$$\begin{gathered} 150=50\times \cos \theta \times 3 \\ \cos \theta =1 \\ \theta =0^0 \end{gathered}$$

Hence the angle $\theta =0^0$

Therefore Option C is the correct answer.