Hoffmann bromamide degradation of benzamide gives product A, which upon heating with CHCl3 and NaOH gives product B. The structures of A and B are:

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The correct option is A

In Hoffmann bromamide degradation of benzamide gives product A (benzamine), which upon heating with CHCl₃ and NaOH gives product B (phenyl isocyanide). The structures of A and B are:
A- benzamine
B- phenyl isocyanide

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Similar questions

Q. What are the constituent amines formed when the mixture of (i) and (ii) undergoes Hoffmann bromamide degradation?

P h (o - D) C O N H_{2} (i) P h C O 15 N H_{2} (i i)

Q. Hoffmann bromamide degradation of benzamide gives product A, which upon heating with

C H C l_{3}

and

N a O H

gives product B. The structures of A and B are :

Q. Write structure and

IUPAC

name of:

A)

the amide which gives propanamine by Hoffmann bromamide reaction.

B)

the amine produced by the Hoffmann degradation of benzamide.

What is produced when ${CH}_{3} {CONH}_{2}$ reacts with $NaOBr$ ? Is $NaOBr$ a product of (or equivalent to) ${Br}_{2} + NaOH$ which are used in the Hoffmann bromamide degradation reaction?

Q. What is the correct structure of the amine produced by the Hoffmann degradation of benzamide ?

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Hoffmann bromamide degradation of benzamide gives product A, which upon heating with CHCl3 and NaOH gives product B. The structures of A and B are:

The correct option is A In Hoffmann bromamide degradation of benzamide gives product A (benzamine), which upon heating with CHCl3 and NaOH gives product B (phenyl isocyanide). The structures of A and B are:A- benzamineB- phenyl isocyanide

The correct option is A

In Hoffmann bromamide degradation of benzamide gives product A (benzamine), which upon heating with CHCl₃ and NaOH gives product B (phenyl isocyanide). The structures of A and B are:
A- benzamine
B- phenyl isocyanide