If 2x2 - 3xy - y2 - x - 2y - 8 - 0- then dy-dx is equal to

Explanation for the correct option:Find the value of dy/dx:Given, 2x^2 – 3xy + y^2 + x + 2y – 8 = 0Differentiate it with respect to x.4x – 3xdy/dx 3y + 2ydy/dx ...

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Byju's Answer

Standard IX

Mathematics

Zeroes of a Polynomial

If 2x2 - 3xy ...

Question

If $2 x^{2} - 3 x y + y^{2} + x + 2 y - 8 = 0$ , then $\frac{d y}{d x}$ is equal to

$\frac{(3 y - 4 x - 1)}{(2 y - 3 x + 2)}$

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$\frac{(3 y + 4 x + 1)}{(2 y + 3 x + 2)}$

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$\frac{(3 y - 4 x + 1)}{(2 y - 3 x - 2)}$

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$\frac{(3 y - 4 x + 1)}{(2 y + 3 x + 2)}$

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Solution

The correct option is A
$\frac{(3 y - 4 x - 1)}{(2 y - 3 x + 2)}$

Explanation for the correct option:
Find the value of $\frac{d y}{d x}$ :
Given, $2 x^{2} - 3 x y + y^{2} + x + 2 y - 8 = 0$
Differentiate it with respect to $x$ .
$4 x - 3 x \frac{d y}{d x} - 3 y + 2 y \frac{d y}{d x} + 1 + 2 \frac{d y}{d x} = 0$
$\Rightarrow$ $\frac{d y}{d x} (2 y - 3 x + 2) = 3 y - 4 x - 1$
$\Rightarrow$ $\frac{d y}{d x} = \frac{(3 y - 4 x - 1)}{(2 y - 3 x + 2)}$
Hence, Option ‘A’ is Correct.

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If 2x2-3xy+y2+x+2y-8=0, then dydx is equal to

The correct option is A 3y-4x-12y-3x+2Explanation for the correct option:Find the value of dydx:Given, 2x2–3xy+y2+x+2y–8=0Differentiate it with respect to x.4x–3xdydx-3y+2ydydx+1+2dydx=0⇒ dydx(2y-3x+2)=3y–4x–1 ⇒ dydx=(3y–4x–1)(2y-3x+2)Hence, Option ‘A’ is Correct.

If $2 x^{2} - 3 x y + y^{2} + x + 2 y - 8 = 0$ , then $\frac{d y}{d x}$ is equal to