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Question

If cos(A+B)=αcosAcosB+βsinAsinB, then (α,β)=?


A

(-1,-1)

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B

(-1,1)

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C

(1,-1)

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D

(1,1)

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Solution

The correct option is C

(1,-1)


Find the value of (α,β):

Given,

cos(A+B)=αcosAcosB+βsinAsinB

By comparing it with cos(A+B)=cosAcosBsinAsinB, we get

α=1,β=-1(α,β)=(1,-1)

Hence, the correct option is C.


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