If cos(A+B)=αcosAcosB+βsinAsinB, then (α,β)=?
(-1,-1)
(-1,1)
(1,-1)
(1,1)
Find the value of (α,β):
Given,
cos(A+B)=αcosAcosB+βsinAsinB
By comparing it with cos(A+B)=cosAcosB–sinAsinB, we get
α=1,β=-1(α,β)=(1,-1)
Hence, the correct option is C.