Question

If the water falls from a dam into a turbine wheel 19.6 m below, then the velocity of water at the turbine is :(take $g=9.8m/{sec}^2$)

• A. 19.6 m/s
• B. 39.0 m/s
• C. 98.8 m/s
• D. 9.8 m/s

Answer 1

The correct option is A 19.6 m/s

$0.5m(v^2-u^2)=mgh$

since $u=0$

$v=\sqrt{2gh}=\sqrt{2\left(9.8\right)19.6}=19.6m/s$