From a waterfall, water is pouring down at the rate of 160 kg per second on the blades of a turbine. If the height of the fall be 50 m, the power delivered to the turbine is approximately equal to
(Take $g = 9.8 m / s^{2}$ )

7.84

\times 10^{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7.84

\times 10^{7}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8400 W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

784 kW

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 7.84 $\times 10^{4}$ W
In the given problem:
$m = 160 k g, h = 50 m, g = 9.8 m / s^{2}, t = 1 s e c$
Putting these values in: $P = \frac{m g h}{t}$ , we get $P = 7.84 \times 10^{4} W$

Suggest Corrections

Similar questions

Q. From a waterfall, water pours down at the rate of

100 k g s^{- 1}

on the blades of a turbine. If the height of the fall is 120 m, what is the power delivered to the turbine?

From a waterfall, water pours down at the rate of $100 k g s^{- 1}$ on the blades of a turbine. If the height of the fall is 120 m, calculate the power delivered to the turbine?
(Given $g = 10 m s^{- 2}$ )

Q. From a water fall , water is pouring down at the rate of 100 kg per sec on the blade of a turbine . If the height of the fall be 100 m, the power delivered to the turbine is approximately equal to :

Q. From a water fall, water is pouring down at the rate 100 kg per see on the blade of a turbine . If the height of the fall be 100 m, the power delivered to the turbine is approximately equal to

From a waterfall, water is falling down at the rate of 100 kg/s on the blades of turbine. If the height of the fall is 100 m, then the power delivered to the turbine is approximately equal to

Join BYJU'S Learning Program

From a waterfall, water is pouring down at the rate of 160 kg per second on the blades of a turbine. If the height of the fall be 50 m, the power delivered to the turbine is approximately equal to (Take g=9.8 m/s2)

The correct option is A 7.84 ×104 WIn the given problem: m=160 kg,h=50 m,g=9.8 m/s2,t=1 secPutting these values in: P=mght, we get P=7.84×104 W

From a waterfall, water is pouring down at the rate of 160 kg per second on the blades of a turbine. If the height of the fall be 50 m, the power delivered to the turbine is approximately equal to
(Take $g = 9.8 m / s^{2}$ )

The correct option is A 7.84 $\times 10^{4}$ W
In the given problem:
$m = 160 k g, h = 50 m, g = 9.8 m / s^{2}, t = 1 s e c$
Putting these values in: $P = \frac{m g h}{t}$ , we get $P = 7.84 \times 10^{4} W$