If (x+iy)(p+iq)=(x2+y2)i, then
p=x,q=y
p=x2,q=y2
x=q,y=p
none of these
Explanation for the correct answer:
To find the value of p,q :
Given,
(x+iy)(p+iq)=(x2+y2)i⇒xp+pyi+xqi-yq=x2+y2i⇒xp-yq+(py+xq)i=(x2+y2)i
Now, on comparing the real and imaginary part
xp-yq=0⇒xp=yq⇒x=yqp(py+xq)=(x2+y2)
Substitute x=yqp
(py+yq2p)=yqp2+y2⇒y(p2+q2)p=y2(q2+p2)p2⇒yp=1⇒y=p
Substitute y in x=yqp
Then x=q
Hence, the correct option is C.