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Question

The decreasing order of basicity of the following amines is


  1. I>II>III>IV

  2. IV>III>I>II

  3. II>I>III>IV

  4. IV>I>II>III

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Solution

The correct option is B

IV>III>I>II


The explanation for the correct option:

Option (B): IV>III>I>II

  1. Compound I has sp2 hybridized nitrogen, and resonance is caused by the lone pairs.
  2. In the compound II, the nitrogen is sp2 hybridized and the lone pair electron is effectively involved in a five-member ring with two carbon-carbon doubles to generate a conjugated system of pi electrons that increases stability or decreases basicity.
  3. Nitrogen is sp2 hybridized in compound (III), and as it is already stable, lone pairs are not implicated in resonance.
  4. In the compound IV nitrogen is sp3 hybridized i.e. less "s" character more basic is the compound.
  5. Hence, it is the correct option.

The explanation for the incorrect options:

Option (A): I>II>III>IV

  1. In the compound IV nitrogen is sp3 hybridized i.e. less "s" character more basic is the compound.
  2. Hence, it is an incorrect option.

Option (C): II>I>III>IV

  1. In the compound IV nitrogen is sp3 hybridized i.e. less "s" character more basic is the compound.
  2. Hence, it is an incorrect option.

Option (D): IV>I>II>III

  1. In the compoundII, the nitrogen is sp2 hybridized and the lone pair electron is effectively involved in a five-member ring with two carbon-carbon doubles to generate a conjugated system of pi electrons that decreases its stability.
  2. Hence, it is an incorrect option

Therefore, the decreasing order of basicity of the amines is IV>III>I>II


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