The differential coefficient of f(logx) where f(x)=logx, is:
xlogx
xlogx-1
logxx
None of these
Differentiating to find the coefficient:
Given that: f(x)=logx
⇒f(logx)=loglogx
Differentiating w.r.t x:
⇒f'(logx)=1logx×1x∵ddxlogx=1x⇒f'(logx)=1xlogx⇒f'(logx)=xlogx-1
Hence, the correct answer is Option (B).